Section 6.1 Learning Check||Please enter your Full Name:|Your Email Address:|Your ID Number or Password:|A 95% confidence interval for the mean m of a population is computed from a random sample and found to be 103. We may conclude that # there is a 95&KPHHASH37; probability that <span style='font-family:Symbol'>m</span> is between 7 and 13. %% there is a 95&KPHHASH37; probability that the true mean is 10 and there is a 95&KPHHASH37; chance that thre true margin of error is 3. %% if we took many additional random samples and from each computed a 95&KPHHASH37; confidence intervals for <span style='font-family:Symbol'>m</span>, approximately 95&KPHHASH37; of these intervals would contain <span style='font-family:Symbol'>m</span>. %% all of the above. %%|The weights of a random sample of 25 females runners are measured. The sample mean is 60 kg. Suppose that the weights of female runners has a normal distribution with a standard deviation of 5 kg. A 95% confirdence interval for the population mean is # (59.61, 60.39) %% (59, 61) %% 58.04, 61.96) %% (50.2, 69.8) %%|Suppose we want a 90% confidence interval for the average amount spent on books by freshperson in their first year at an university. The interval is to have a margin of error of$2, and the amount spent has a normal distribution with a standard deviation $30. The number of observations required is closest to # 25. %% 30. %% 609. %% 865. %%