flyingtable83@yahoo.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
wbrandsmeier@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|uniform distribution on 0, 1, 2, 3, 4.|0.6723|2|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
arudnicki@msn.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.2000
fmxavier05@hotmail.com|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.3277|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0148|0.2266
montgome@citrine.indstate.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
kylebentfield@hotmail.com|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
jalen04|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.7734
reax0015|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
jalen_4|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
chan0560@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.2266
7|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|1.414|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
twhyatt@runestone.net|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
hayn0035@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
Lovelys83@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.7734
wagn0339@morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.2266
duer0036@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0007|0.5000
mahlingp|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.2186|0.5000
mahlingpo|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
mahlingpoo|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
mahlingpooo|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
gbuttweiler@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
clueck@tds.net|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
lrupp@mnba.org|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
leahmullenbach@yahoo.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0148|0.2000
rada0028@morris.umn.edu|none of the above.|normal distribution with mean 2 and variance 1.|0.3277|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.7734
missbb96@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
olso1576@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2266
delmax_f@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=10 and p=0.5.|0.0400|6|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.2000
jayren96@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.0400|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.5000
ee|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.3277|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.2266
moll0091@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0001|0.5000
mirvin2@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
sungur|none of the above.|binomial distribution with n=10 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.2000
srice@rea-alp.com|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.7734
Als3rdhand@aol.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
gilk0008@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
mj0599@excite.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=10 and p=0.5.|0.3277|6|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.2266
yerkaj@cda.morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
mitc0246|none of the above.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.7734
spalmquist@charter.net|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.2186|0.2266
lukezajac@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
john4296@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0007|0.2266
kirkir12@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.3277|6|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.7734
sungurea@cda.morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.2000
nowa0053@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
kirk0109@umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.2266
ringernj@cda.morris.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
nist0022@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
dalr0006@mrs.umn, patn0019@mrs.umn|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.7734
arnd0090@umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0007|0.7734
gund0210@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
Moll0089, Souk0034|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.7734
kram0201@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.2000
AMANAXIS@HOTMAIL.COM|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
stem0042|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
derr0022@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0007|0.5000
carlyrdahl@aol.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.2266
kuec0017|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.2266
helm0132|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.2000
PFur538447@aol.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2000
sadf|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
mawinans@charter.net|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
musical1704@yahoo.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0007|0.7734
avaf@ll.net|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|6|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.7734
phel0073@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.2000
phel0070@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.7734
eldanio85@yahoo.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
Talis3548@aol.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.7734
dfbarger@juno.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
vegan_like_me@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.5000
nord0381@cda.morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
dunrovin@astound.net|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0007|0.5000
olsater@brainerd.k12.mn.us|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.6723|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.2000
determam@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0148|0.7734
smit@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2266
john4125@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.2266
patt0210@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
lpl767@attbi.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
super_8_gk@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.2000
madd0090@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.7734
john4195|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0001|0.2266
jrevenso5689@winona.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
mcescher@aol.com|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
abra0051@morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
woodsdana@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.5000
5156@d2165|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.7734
buttonman_ipsfan@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.7734
mein0062|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.7734
elto0012@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.2266
obr0301|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.2266
olso1545@umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0006|0.5000
hocu0001@morris.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.2266
mart1150|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.7734
mart1238@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.7734
loeh0022|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
fenn0037@mrs|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
marg0047|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.7734
marg0048|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
lkjf|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.2266
fgsszd|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
fdg|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
ang6203@netscape.net|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
helm0166@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.7734
chillywilly_54@hotmail.com|none of the above.|normal distribution with mean 2 and variance 1.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.2266
karla_j_koenig@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
darc0004@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.7734
kknudsen12@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
josto22@hotmail.com|none of the above.|uniform distribution on 0, 1, 2, 3, 4.|0.3277|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.5000
andr0456@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
cristinahartnett@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
smit2085@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
curt9087@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
orangeskier1081@Hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.5000
biggie2004@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
insane_boy@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0006|0.5000
vfl;|a normal distribution with a mean of 20.|normal distribution with mean 2 and variance 1.|0.0400|1.414|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0006|0.5000
vf9|a normal distribution with a mean of 20.|normal distribution with mean 2 and variance 1.|0.0400|2|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0006|0.5000
vf|a normal distribution with a mean of 20.|normal distribution with mean 2 and variance 1.|0.0400|3|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0006|0.5000
a|a normal distribution with a mean of 20.|uniform distribution on 0, 1, 2, 3, 4.|0.00032|3|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.2266
r|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.0400|2|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.2186|0.5000
youn0656@morris.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
sherrypopowski@mail.ogc.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
klsmith@csbsju.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2000
drap0026@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
emylee908@yahoo.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
jplarson@mchsi.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.7734
randinorby@charter.net|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
hynn0004@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
chen0863@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.7734
trom0029@morris.umn.edu|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
jj_klick16@hotmail.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
harr0709@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
zaba0004|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
Lb56241@yahoo.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.7734
chit_31@yahoo.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
edlu0029@morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
l@yahoo.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
dtfeldhege@warpdriveonline.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.5000
blas0063@morris.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.7734
ke_anderson@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
east0120@morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2266
ericaolson@lakeland.ws|none of the above.|binomial distribution with n=10 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.2266
the_goat_grrl@yahoo.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
mall0113@morris.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
enge0335@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.7734
Deserteagle@frontiernet.net|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
redm0054@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
medl0023@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
Sarah.R.Kron@wheaton.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.6723|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
afroman2k6@yahoo.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
schaubz@yahoo.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
kroll072@mrs.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
TomKelsey@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
eli_ana2005@yahoo.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.7734
nay_nay_2006@hotmail.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
mark0387@mrs.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.5000
cannongal@earthlink.net|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
musi0022@mrs.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
kees0020@mrs.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
dk@dk.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
dk@dkl.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
Smthjanel@yahoo.com|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.3277|6|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.2000
adsf|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.3277|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.2000
sand0653@mrs.umn.edu|none of the above.|binomial distribution with n=10 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.2266
llll|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.6723|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0006|0.2266
hage0369@tc.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
satr0013@umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
greatgalwoody@yahoo.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.2000
musi0026@morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
tomandamy@gmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0001|0.5000
melissa0848@msn.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
pete2506@umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|1.414|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0001|0.5000
mini0018@mrs.umn.edu|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
melb0082@morris.umn.edu|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
foxx0226@ morris.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.2186|0.5000
JKSK8terboy@hotmail.com|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.2000
hagg0055|a binomial distribution with mean 20.|binomial distribution with n=10 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0148|0.7734
markandrie@hotmail.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.00032|3|2|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.7734
supersefie@yahoo.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.5000
grif0227@morris.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0006|0.5000
free0208@umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0001|0.5000
tess0052@mrs.umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.2266
scal0029@mrs.umn.edu|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.7734
russ.haywood@gMail.coM|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0148|0.7734
 |a normal distribution with a mean of 20.|uniform distribution on 0, 1, 2, 3, 4.|0.00032|1.414|6|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0001|0.7734
colso009@morris.umn.edu|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.0006|0.2000
jenn0117|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is less than 0.0001|0.0006|0.5000
caitlin_maguire@hotmail.com|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0006|0.2000
baso0011@mrs.umn.edu|a binomial distribution with mean 20.|normal distribution with mean 2 and variance 1.|0.0400|3|6|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.0148|0.2000
joh01673@morris.umn.edu|none of the above.|uniform distribution on 0, 1, 2, 3, 4.|0.00032|6|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.7734
lofg0020@umn.edu|a binomial distribution with 40 trials but success probability not equal to 0.5.|binomial distribution with n=4 and p=0.5.|0.00032|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.50|0.0001|0.5000
croo0049|a binomial distribution with mean 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.5000
stars30@hotmail.com|a normal distribution with a mean of 20.|binomial distribution with n=4 and p=0.5.|0.0400|3|1.414|The probability that proportion of 1500 adults who support the increase is more than 0.5 is 0.4601|0.2186|0.5000
wesnf@elkf.com|none of the above.|binomial distribution with n=4 and p=0.5.|0.3277|3|3|The probability that proportion of 1500 adults who support the increase is more than 0.5 is about 0.10|0.2186|0.2266