Suppose a box contains 4 tickets labeled by

Let us choose one ticket at random, and consider the random events

A={1 occurs at the first place}

B={1 occurs at the second place}

C={1 occurs at the third place}

P(A)=1/2 P(B)=1/2 P(C)=1/2

AB={112} AC={121} BC={211}

P(AB)=P(AC)=P(BC)=1/4

So we conclude that the three events A, B, C are pairwise independent.

However, ABC is an empty set and

P(ABC)=0

but

P(A)P(B)P(C)=1/8.